The University of North Carolina at Pembroke
Using SOLVER in Lotus 1-2-3 Rel. 5

 


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To perform a linear programming problem in Lotus 1-2-3, follow these steps:

1.  In a spreadsheet, set up a matrix of coefficients for the constraints and for the objective function.
    Note that the whole inequality for the constraint is included in a cell--including the inequality sign (<= or >=, as appropriate) and the value for the right-hand side of the inequality.  When Lotus evaluates this cell it will show a 1 or a 0 depending on whether the inequality is true or false.
    It is necessary to specify the non-negativity constraints explicitly.
 

A B C D E F
 1 Constraints X1 X2 X3 Formulas  
 2 Labor time 64 33 14 @sumproduct(b2..d2,b$9..d$9)<=400
 3 Machine time 50 60 9 @sumproduct(b3..d3,b$9..d$9)<=400
 4 Management time 3 3 3 @sumproduct(b4..d4,b$9..d$9)<=80
 5 Non-negativity of X1 1 0 0 +b9>=0
6 Non-negativity of X2 0 1 0 +c9>=0
7 Non-negativity of X3 0 0 1 +d9>=0
 8 Objective Function 3.5 0.45 2.2 @sumproduct(b6..d6,b$9..d$9)
 9 Decision Variables 1 1 1
 10

2.  Click on Range, then Analyze, then Solver.

3.  Enter the instructions in the Solver Definition box.

 
last updated January 26, 2001, by James R. Frederick
copyright 2001 by James R. Frederick